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NEET Sample Paper NEET Sample Test Paper-42

  • question_answer
    When photons of energy hu fall on an aluminium plate photoelectrons of maximum kinetic energy K are ejected If the frequency of the radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be:

    A) \[\operatorname{K} + {{E}_{o}}\]                     

    B) 2K  

    C) K                                 

    D) \[\operatorname{K}+hv\]

    Correct Answer: D

    Solution :

    using Einstein equation of photoelectric effect \[\operatorname{W}={{\phi }_{o}}+KE\] \[hv={{\phi }_{o}}+K\] \[{{\phi }_{o}}=hv-K\]                           ?.(1) If frequency of incident is double \[2hv={{\phi }_{o}}+{{K}_{1}}\]                                 .?(2) By using equation                       \[2hv=(hv-K)+{{K}_{}}\left( {{\phi }_{o}}=hv-K \right)\] \[{{\operatorname{K}}_{l}}=hv+K\]


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