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NEET Sample Paper NEET Sample Test Paper-42

  • question_answer
    The work done in turning a magnet of magnetic moment M by an angle of \[90{}^\circ \] from the meridian is n times the corresponding work done to turn it through an angle of\[60{}^\circ \].

    A) \[\operatorname{n}=\frac{1}{2}\]                      

    B) n=2  

    C) \[\operatorname{n}=\frac{1}{4}\]                      

    D) n = 1

    Correct Answer: B

    Solution :

    \[{{\operatorname{W}}_{1}}=MB\,\left[ Cos\,\,{{0}^{o}}-Cos\,\,90 \right]\] \[=MB\left[ 1-0 \right]\] \[{{\operatorname{W}}_{1}}=MB\] In second case                            ?.(1) \[{{\operatorname{W}}_{2}}=MB\,\left[ Cos\,\,{{0}^{o}}-Cos\,\,6{{0}^{\operatorname{o}}} \right]\] \[{{\operatorname{W}}_{2}}=\frac{MB}{2}\]                             ?.(2) \[\left( 1 \right)\div \left( 2 \right)\] \[\frac{{{W}_{1}}}{{{W}_{2}}}=2\]


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