• # question_answer When during electrolysis of a solution of $AgN{{O}_{3}},$9650 coulombs of charge pass through the electroplating both, the mass of silver deposited on the cathode will be A)  $1.08\text{ }g$                     B)  $10.8\text{ }g$C)  $21.6\text{ }g$                     D)  $108\,g$

$\because$  On passing 96500 C silver deposited = 108 g On passing 9650 C silver will deposite $=\frac{108}{96500}\times 9650$ $=10.8\,g$