• question_answer The correct order of bond angles in ${{H}_{2}}S,\,N{{H}_{3}},B{{F}_{3}}$ and $Si{{H}_{4}}$ is A)  ${{H}_{2}}S>Si{{H}_{4}}<N{{H}_{3}}<B{{F}_{3}}$ B)  $N{{H}_{3}}<{{H}_{2}}S<Si{{H}_{4}}<B{{F}_{3}}$ C)  ${{H}_{2}}S<N{{H}_{3}}<Si{{H}_{4}}<B{{F}_{3}}$ D)  ${{H}_{2}}S<N{{H}_{3}}<B{{F}_{3}}<Si{{H}_{4}}$

The correct order of bond angle is as:  ${{H}_{2}}S$    < $N{{H}_{3}}$     < $Si{{H}_{4}}$   < $B{{F}_{3}}$ ${{92.6}^{o}}$ ${{107}^{o}}$ ${{109}^{o}}28'$ ${{120}^{o}}$