JEE Main & Advanced Sample Paper JEE Main - Mock Test - 18

  • question_answer
    Three rods of same dimensions have thermal conductivities 3K, 2K and K respectively.
    They are arranged as shown below
    What will be the temperature T of the junction?

    A) \[\frac{200}{3}\,{{\,}^{o}}C\] 

    B) \[\frac{100}{3}\,{{\,}^{o}}C\]

    C) \[75\,{{\,}^{o}}C\]      

    D) \[\frac{50}{3}{{\,}^{o}}C\]

    Correct Answer: A

    Solution :

    [a]: Let L and A be length and area of cross- section of each rod. At steady state,\[{{H}_{1}}={{H}_{2}}+{{H}_{3}}\] \[\frac{(100-T)(3K)A}{L}=\frac{(T-50)2KA}{L}+\frac{(T-0)KA}{L}\] \[3(100-T)=2(T-50)+T\] \[300-3T=2r-100+T\] \[6T=400\]or\[T=\frac{400}{6}=\frac{200}{3}{{\,}^{o}}C\]


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