A) 2.2 MeV
B) 1.1 MeV
C) 0.5 MeV
D) 0.25 MeV
Correct Answer: B
Solution :
[b]: Here, \[{{m}_{p}}=1.007825u,{{m}_{n}}=1.008665u\]mass of\[_{1}{{H}^{2}}\] nucleus, \[{{m}_{N}}{{(}_{1}}{{H}^{2}})=2.014102u\] The deuteron nucleus contains one proton and one neutron. Therefore, mass of nucleons constituting deuteron, \[{{m}_{p}}+{{m}_{n}}=1.007825+1.008665=2.01649u\] Mass defect, \[\Delta M=({{m}_{p}}+{{m}_{n}})-{{m}_{N}}{{(}_{1}}{{H}^{2}})\] \[=2.01649-2.014102=0.002388u\] \[=0.002388\times 931.5\text{ }Me\text{ }V/{{c}^{2}}\] \[=2.224\text{ }Me\text{ }V/{{c}^{2}}\] Binding energy, \[{{E}_{b}}=\Delta M{{c}^{2}}=2.224\text{ }MeV\] Binding energy per nucleon \[=\frac{{{E}_{b}}}{A}=\frac{2.224}{2}=1.112MeV\]
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