A) \[AB=BA\]
B) \[{{A}^{2}}+{{B}^{2}}={{A}^{2}}-{{B}^{2}}\]
C) \[{A}'{B}'=AB\]
D) None of these
Correct Answer: A
Solution :
Since \[(A+B)(A-B)={{A}^{2}}-{{B}^{2}}\] By matrix distribution law, Þ \[{{A}^{2}}-AB+BA-{{B}^{2}}={{A}^{2}}-{{B}^{2}}\] Þ \[BA-AB=0\,\,\Rightarrow BA=AB\].
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