JEE Main & Advanced Mathematics Determinants & Matrices Question Bank Types of matrices, Algebra of matrices

  • question_answer
    \[A=\left[ \begin{matrix}    5 & -3  \\    2 & 4  \\ \end{matrix} \right]\]and \[B=\left[ \begin{matrix}    6 & -4  \\    3 & 6  \\ \end{matrix} \right],\]then \[A-B=\]  [RPET 1995]

    A) \[\left[ \begin{matrix}    11 & -7  \\    5 & 10  \\ \end{matrix} \right]\]

    B) \[\left[ \begin{matrix}    -1 & \text{   }1  \\    -1 & -2  \\ \end{matrix} \right]\]

    C) \[\left[ \begin{matrix}    11 & 7  \\    5 & -10  \\ \end{matrix} \right]\]

    D) \[\left[ \begin{matrix}    12 & -7  \\    5 & -10  \\ \end{matrix} \right]\]

    Correct Answer: B

    Solution :

    \[A=\left[ \begin{matrix}    5 & -3  \\    2 & 4  \\ \end{matrix} \right]\]and \[B=\left[ \begin{matrix}    6 & -4  \\    3 & 6  \\ \end{matrix} \right]\],        \ \[A-B=\left[ \begin{matrix}    -1 & \,\,\,1  \\    -1 & -2  \\ \end{matrix} \right]\].


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