A) \[\frac{12}{5}\]
B) \[\frac{12}{13}\]
C) \[\frac{13}{12}\]
D) \[\frac{5}{12}\]
Correct Answer: B
Solution :
(b): \[AB=14-9=5\] \[BC=12;AC=\sqrt{{{5}^{2}}+{{12}^{2}}}=13\Rightarrow \sin \theta =\frac{BC}{AC}=\frac{12}{13}\]
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