A) \[\frac{12}{5}\]
B) \[\frac{5}{12}\]
C) \[\frac{12}{5}\]
D) \[\frac{12}{13}\]
Correct Answer: D
Solution :
(d): \[\phi +e={{90}^{{}^\circ }}\] \[\phi =\left( {{90}^{{}^\circ }}-\theta \right)\] \[cos\phi =cos\left( 90-\theta \right)\] \[=sin\theta \] \[sin\theta =\frac{12}{13}\]
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