JEE Main & Advanced Physics Thermodynamical Processes Question Bank Topic Test - Thermodynamical Process (2021)

  • question_answer
    Helium at \[{{27}^{o}}C\] has a volume of 8 litres. It is suddenly compressed to a volume of 1 litre. The temperature of the gas will be \[[\gamma =5/3]\]

    A) \[{{108}^{o}}C\]

    B) \[{{9327}^{o}}C\]

    C) \[{{1200}^{o}}C\]

    D) \[{{927}^{o}}C\]

    Correct Answer: D

    Solution :

    [d] \[T{{V}^{\gamma -1}}=\]constant\[\Rightarrow {{T}_{2}}={{T}_{1}}{{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma -1}}={{927}^{o}}C\]

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