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JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Solution of quadratic inequations and Miscellaneous equations

  • question_answer
    The roots of the equation \[{{x}^{4}}-4{{x}^{3}}+6{{x}^{2}}-4x+1=0\] are  [MP PET 1986]

    A) 1, 1, 1, 1

    B) 2, 2, 2, 2

    C) 3, 1, 3, 1

    D) 1, 2, 1, 2

    Correct Answer: A

    Solution :

    Let \[f(x)={{x}^{4}}-4{{x}^{3}}+6{{x}^{2}}-4x+1=0\] Þ \[(x-1)({{x}^{3}}-3{{x}^{2}}+3x-1)=0\] Þ \[(x-1){{(x-1)}^{3}}=0\]Þ \[x=1,\,1,\,1,\,1\]


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