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JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Solution of quadratic inequations and Miscellaneous equations

  • question_answer
    If \[{{x}^{2}}+2ax+10-3a>0\] for all \[x\in R\], then  [IIT Screening 2004]

    A) \[-5<a<2\]

    B) \[a<-5\]

    C) \[a>5\]

    D) \[2<a<5\]

    Correct Answer: A

    Solution :

    According to given condition,           \[4{{a}^{2}}-4(10-3a)<0\]Þ\[{{a}^{2}}+3a-10<0\] Þ\[(a+5)\,(a-2)<0\] Þ \[-5<a<2\].


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