A) 3
B) 2
C) 1
D) None of these
Correct Answer: B
Solution :
Given, \[\log (-2x)=2\log (x+1)\] \[\Rightarrow -2x={{(x+1)}^{2}}\] \[\Rightarrow {{x}^{2}}+4x+1=0\] Þ \[x=\frac{-4\pm \sqrt{16-4}}{2}\] Þ \[x=\frac{-4\pm \sqrt{12}}{2}\] Þ \[x=-2\pm \sqrt{3}\]Þ \[x=(-2+\sqrt{3}),(-2-\sqrt{3})\].You need to login to perform this action.
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