A) \[x<-\,2\] or \[x>6\]
B) \[-\,6<x<2\]
C) \[2<x<6\]
D) \[-\,2<x<6\]
Correct Answer: D
Solution :
\[{{x}^{2}}-4x<12\] Þ \[{{x}^{2}}-4x-12<0\] Þ \[{{x}^{2}}-6x+2x-12<0\] Þ \[(x-6)(x+2)<0\] Þ \[-2<x<6\].
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