A) log x
B) \[\log (e-1)\]
C) 0
D) 1
Correct Answer: B
Solution :
Here \[\frac{f(b)-f(a)}{b-a}=f'(c)\] Þ \[\frac{{{e}^{b}}-{{e}^{a}}}{b-a}=f'(c)\]Þ\[\frac{e-1}{1-0}={{e}^{c}}\Rightarrow c=\log (e-1)\].You need to login to perform this action.
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