A) 1-butene
B) 2-butane
C) 1-butanol
D) 2-butanol
Correct Answer: A
Solution :
\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}-Cl+KOH(\text{alc}\text{.})\to \]\[\underset{\text{1-butene}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{3}}C{{H}_{2}}-CH=C{{H}_{2}}+KCl+{{H}_{2}}O}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
