A) \[X=KCN,\,Y=LiAl{{H}_{4}}\]
B) \[X=KCN,\,Y={{H}_{3}}{{O}^{+}}\]
C) \[X=C{{H}_{3}}Cl,\,Y=AlC{{l}_{3}}/HCl\]
D) \[X=C{{H}_{3}}N{{H}_{2}},Y=HN{{O}_{2}}\]
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{5}}Br\xrightarrow{KCN(X)}{{C}_{2}}{{H}_{5}}CN\xrightarrow{LiAl{{H}_{4}}(Y)}\]\[{{C}_{2}}{{H}_{5}}C{{H}_{2}}N{{H}_{2}}({{C}_{3}}{{H}_{7}}N{{H}_{2}})\] \[X=KCN,\,Y=LiAl{{H}_{4}}\]
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