A) \[\sqrt{6}+\sqrt{3}\]
B) \[\sqrt{7}+\sqrt{2}\]
C) \[\sqrt{8}+\sqrt{1}\]
D) \[\sqrt{5}+\sqrt{4}\]
Correct Answer: C
Solution :
(c): \[{{\left( \sqrt{6}+\sqrt{3} \right)}^{2}}=6+3+2\sqrt{18}=9+2\sqrt{18}\] \[{{\left( \sqrt{7}+\sqrt{2} \right)}^{2}}=7+2+2\sqrt{14}=9+2\sqrt{14}\] \[\sqrt{7}+\sqrt{1}=8+1+2\sqrt{18}=9+2\sqrt{18}\] \[\sqrt{5}+\sqrt{4}=5+4+2\sqrt{20}=9+2\sqrt{20}\] Hence \[\sqrt{8}+\sqrt{1}\] is smallest
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