A) \[\sqrt{11}-\sqrt{9}\]
B) \[\sqrt{5}-\sqrt{3}\]
C) \[\sqrt{7}-\sqrt{5}\]
D) \[\sqrt{13}-\sqrt{11}\]
Correct Answer: B
Solution :
(b): \[\sqrt{11}-\sqrt{9}\times \frac{\sqrt{11}+\sqrt{9}}{\sqrt{11}+\sqrt{9}}=\frac{2}{\sqrt{11}+\sqrt{9}};\]\[\sqrt{7}-\sqrt{5}\times \frac{\sqrt{7}+\sqrt{5}}{\sqrt{7}+\sqrt{5}}=\frac{2}{\sqrt{7}+\sqrt{5}}\] \[\sqrt{5}-\sqrt{3}\times \frac{\sqrt{5}+\sqrt{3}}{\sqrt{5}+\sqrt{3}}=\frac{2}{\sqrt{5}+\sqrt{3}};\]\[\sqrt{13}-\sqrt{11}\times \frac{\sqrt{13}+\sqrt{11}}{\sqrt{13}+\sqrt{11}}=\frac{2}{\sqrt{13}+\sqrt{11}}\] Hence, \[\sqrt{5}-\sqrt{3}\] is the greatest
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