A) \[{{C}_{2}}{{H}_{5}}I+C{{H}_{3}}OH\]
B) \[C{{H}_{3}}I+{{H}_{2}}O\]
C) \[{{C}_{2}}{{H}_{5}}OH+{{H}_{2}}O\]
D) \[{{C}_{2}}{{H}_{5}}OH+C{{H}_{3}}I\]
Correct Answer: D
Solution :
\[{{C}_{2}}{{H}_{5}}OC{{H}_{3}}+Hl\to {{C}_{2}}{{H}_{5}}OH+C{{H}_{3}}l\] Halogen goes with the smaller group on cleavage of ether.
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