A) 1 mol acetic acid + 1 mol ethyl alcohol
B) 1 mol ethyl alcohol + 1 mol methyl alcohol
C) 2 moles of ethyl alcohol
D) 1 mol of 2-butanol.
Correct Answer: C
Solution :
\[\underset{Ethyl\,aceate}{\mathop{C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}}}\,\xrightarrow[or\,{{H}_{2}}/Pt]{LiA{{H}_{4}}/{{H}_{3}}{{O}^{+}}}C{{H}_{3}}C{{H}_{2}}OH+{{C}_{2}}{{H}_{5}}OH\]You need to login to perform this action.
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