JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    \[{{\sin }^{-1}}\frac{1}{\sqrt{5}}+{{\cot }^{-1}}3\]is equal to   [MP PET 1993; Karnataka CET 1995]

    A) \[\frac{\pi }{6}\]

    B) \[\frac{\pi }{4}\]

    C) \[\frac{\pi }{3}\]

    D) \[\frac{\pi }{2}\]

    Correct Answer: B

    Solution :

    \[{{\sin }^{-1}}\frac{1}{\sqrt{5}}+{{\cot }^{-1}}3={{\cot }^{-1}}\left( \frac{\sqrt{1-\frac{1}{5}}}{\frac{1}{\sqrt{5}}} \right)+{{\cot }^{-1}}3\] \[={{\cot }^{-1}}(2)+{{\cot }^{-1}}(3)={{\cot }^{-1}}\left( \frac{2\times 3-1}{3+2} \right)={{\cot }^{-1}}(1)=\frac{\pi }{4}\].


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