JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    If \[{{\cos }^{-1}}x+{{\cos }^{-1}}y=2\pi ,\]then \[{{\sin }^{-1}}x+{{\sin }^{-1}}y\]is equal to

    A) \[\pi \]

    B) \[-\pi \]

    C) \[\frac{\pi }{2}\]

    D) None of these

    Correct Answer: B

    Solution :

    \[{{\cos }^{-1}}x+{{\cos }^{-1}}y=2\pi \] \[\Rightarrow \frac{\pi }{2}-{{\sin }^{-1}}x+\frac{\pi }{2}-{{\sin }^{-1}}y=2\pi \] \[\Rightarrow \pi -({{\sin }^{-1}}x+{{\sin }^{-1}}y)=2\pi \] \[\Rightarrow {{\sin }^{-1}}x+{{\sin }^{-1}}y=-\pi \]


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