A) \[s{{p}^{3}}{{d}^{2}}\]
B) \[s{{p}^{3}}\]
C) \[s{{p}^{3}}d\]
D) \[s{{p}^{2}}d\]
Correct Answer: A
Solution :
\[Xe{{F}_{4}}\] has \[s{{p}^{3}}{{d}^{2}}\] hybridisation, its shape is square planar.
You need to login to perform this action.
You will be redirected in
3 sec
