A) \[:\,\underset{.\,.}{\overset{\,\,\,.\,.}{\mathop{Cl}}}\,\,:\,\underset{.\,.}{\overset{\,\,\,.\,.}{\mathop{Cl}}}\,\,:\]
B) \[:\,\underset{.\,.}{\overset{\,\,\,.\,.}{\mathop{C{{l}^{-}}}}}\,\,:\,\,:\,\,\underset{.\,.}{\overset{\,.\,.}{\mathop{C{{l}^{+}}}}}\,\,:\]
C) \[:\,\underset{{}}{\overset{\,\,\,.\,.}{\mathop{Cl}}}\,\,:\,\underset{{}}{\overset{\,\,\,.\,.}{\mathop{Cl}}}\,\,:\]
D) \[:\,\underset{{}}{\overset{\,\,\,.\,.}{\mathop{Cl}}}\,\,:\,\underset{{}}{\overset{\,\,\,.\,.}{\mathop{\,:\,Cl}}}\,\,:\]
Correct Answer: A
Solution :
\[:\underset{..}{\mathop{\overset{..}{\mathop{Cl}}\,}}\,\,\cdot \,\cdot \underset{..}{\mathop{\overset{..}{\mathop{Cl}}\,}}\,:\] is the correct electronic formula of \[C{{l}_{2}}\]molecule because each chlorine has 7 electrons in its valence shell.
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