A) ` 14.92
B) ` 14
C) ` 16
D) ` 13
Correct Answer: A
Solution :
(I) \[s=\frac{10+10+10}{2}=15\,cm\] \[\therefore \]Area of \[I=\sqrt{15\times 5\times 5\times 5}=25\sqrt{3}\,c{{m}^{2}}\] \[=43.3\,c{{m}^{2}}\] (II) \[s=\frac{10+9+3}{2}=11\,cm\] \[\therefore \] Area of \[II=2\sqrt{11\times 1\times 2\times 8}=8\sqrt{11}\,c{{m}^{2}}\] \[=26.48\,c{{m}^{2}}\] (IV) \[s=\frac{20+20+4}{2}=22\,cm\] \[\therefore \]Area of \[IV=2\sqrt{22\times 2\times 2\times 18}\] \[=24\sqrt{11}c{{m}^{2}}=79.44\,c{{m}^{2}}\] \[\therefore \]Total area of coloured paper used \[=(43.3+26.48+79.44)c{{m}^{2}}=149.22\,c{{m}^{2}}\] Cost of coloured paper used \[=\frac{10}{100}\times 149.22\] = ` 14.92You need to login to perform this action.
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