A) 64 cm
B) 46 cm
C) 84 cm
D) 54 cm
Correct Answer: A
Solution :
Let the other two equal sides of an isosceles triangle be a cm. Then, \[s=\frac{a+a+24}{2}=(a+12)\,cm\] Area of triangle \[=192\,c{{m}^{2}}=192\,c{{m}^{2}}\] \[\Rightarrow \]\[\sqrt{(a+12)(a+12-a)(a+12-a)(a+12-24)}=192\] \[\Rightarrow \]\[144({{a}^{2}}-144)={{(192)}^{2}}\] \[\Rightarrow \]\[{{a}^{2}}=400\Rightarrow a=20\,cm\] \[\therefore \]Perimeter = 20 + 20 + 24 = 64 cm
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