A) OB \[\times \]e in eV
B) OB in volt
C) OA in eV
D) The slope of the line AB
Correct Answer: A
Solution :
Using Einstein?s equation, \[{{V}_{0}}=\left( \frac{h}{e} \right)\,\nu -\frac{{{W}_{0}}}{e}\] Comparing this equation with \[y=mx+c\] We get intercept on ? V0 axis \[=\frac{{{W}_{0}}}{e}\] Þ \[OB=\frac{{{W}_{0}}}{e}\] Þ \[{{W}_{0}}=OB\times e\]You need to login to perform this action.
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