A) Slope of the line
B) Product of slope on the line and charge on the electron
C) Product of intercept along Y-axis and mass of the electron
D) Product of Slope and mass of electron
Correct Answer: B
Solution :
\[{{K}_{\max }}=h\nu -h{{\nu }_{0}}\] Þ \[e{{V}_{0}}=h\nu -h{{\nu }_{0}}\]Þ \[{{V}_{0}}=\frac{h}{e}\nu -\frac{h{{\nu }_{0}}}{e}\] Comparing this equation with \[y=mx+c\], we get slope \[m=\frac{h}{e}\] Þ \[h=m\times e\].
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