JEE Main & Advanced Mathematics Sequence & Series Question Bank Geometric Progression

  • question_answer
    The first term of a G.P. is 7, the last term is 448 and sum of all terms is 889, then the common ratio is  [MP PET 2003]

    A) 5

    B) 4

    C) 3

    D) 2

    Correct Answer: D

    Solution :

    \[a=7\,\,\text{and}\,\,a{{r}^{n-1}}=448\] Now,\[{{S}_{n}}=\frac{a({{r}^{n}}-1)}{r-1}=889\]\[\Rightarrow \frac{(a{{r}^{n-1}}.r-a)}{r-1}=889\] Þ \[\frac{448r-7}{r-1}=889\] Þ \[r=2\].


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