JEE Main & Advanced Mathematics Sequence & Series Question Bank Geometric Progression

  • question_answer
    The sum of a G.P. with common ratio 3 is 364, and last term is 243, then the number of terms is [MP PET 2003]

    A) 6

    B) 5

    C) 4

    D) 10

    Correct Answer: A

    Solution :

    \[\frac{a{{r}^{n}}-a}{r-1}=364\]\[\Rightarrow \frac{a{{r}^{n-1}}.r-a}{r-1}=364\] ?..(i) Þ \[\frac{3\times 243-a}{2}=364\]  \[\Rightarrow a=1\] Now, putting this in (i), n = 6.


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