JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Condition for common roots, Quadratic expressions and Position of roots

  • question_answer
    If \[x\] be real, then the minimum value of \[{{x}^{2}}-8x+17\] is [MNR 1980]

    A) -1

    B) 0

    C) 1

    D) 2

    Correct Answer: C

    Solution :

       \[\frac{-4x}{p+q+r}\] Since x is real, so \[{{(x-4)}^{2}}\] is always positive and its least value is 0 and so the minimum value of given expression is 1.


You need to login to perform this action.
You will be redirected in 3 sec spinner