A) (3, 4)
B) (4, 5)
C) (4, 3)
D) (5, 4)
Correct Answer: D
Solution :
\[{{x}^{2}}-3x+2\]be factor of \[{{x}^{4}}-p{{x}^{2}}+q=0\] Hence \[({{x}^{2}}-3x+2)=0\,\,\Rightarrow (x-2)(x-1)=0\] Þ \[x=2,\,1,\]putting these values in given equation so \[4p-q-16=0\] .....(i) and \[p-q-1=0\] .....(ii) Solving (i) and (ii), we get (p, q)=(5, 4)You need to login to perform this action.
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