A) \[72\ g\]
B) \[36\ g\]
C) \[48\ g\]
D) \[24\ g\]
Correct Answer: A
Solution :
\[\underset{1\text{mole}}{\mathop{Mg}}\,+\underset{0.5\text{mole}}{\mathop{\frac{1}{2}{{O}_{2}}}}\,\to MgO\] 0.5 mole of oxygen react with 1 mole of Mg 1.5 mole of oxygen react with \[\frac{1.5}{0.5}=3\]mole \[24\times 3=72gm\].
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