A) \[5.5\ g\]
B) \[11\ g\]
C) \[22\ g\]
D) \[33\ g\]
E) \[44\ g\]
Correct Answer: C
Solution :
\[\underset{100g}{\mathop{CaC{{O}_{3}}}}\,+\underset{2N}{\mathop{2HCl}}\,\to CaC{{l}_{2}}+\underset{44\ g}{\mathop{C{{O}_{2}}}}\,+{{H}_{2}}O\] 100 g \[CaC{{O}_{3}}\] with 2 N HCl gives 44 g \[C{{O}_{2}}\] 100 g \[CaC{{O}_{3}}\] with 1 N HCl gives 22 g \[C{{O}_{2}}\]
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