A) \[1\centerdot 6\times {{10}^{-11}}J\]
B) \[0\centerdot 5\times {{10}^{-23}}J\]
C) \[-1\centerdot 6\times {{10}^{-11}}J\]
D) \[-3\centerdot 2\times {{10}^{-22}}J\]
Correct Answer: C
Solution :
As \[\Delta U={{q}_{0}}\Delta V=\left( 1\,.\,6\times {{10}^{-19}} \right)\] \[\times \,\left( -1\,.\,0\times {{10}^{8}}V \right)=-1\,.\,6\times {{10}^{-11}}\,V\]
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