question_answer

Directions: (6-10)

Potential Energy of the Proton

Potential difference \[\left( \Delta V \right)\]between two points A and B separated by a distance x, in a uniform electric field E is given by \[\Delta V=-Ex\], where x is measured parallel to the field lines. If a charge qo moves from P to Q, the change in potential energy \[\left( \Delta U \right)\]is given as \[\Delta U={{q}_{0}}\Delta V\]. A proton is released from rest in uniform electric field of magnitude \[4\centerdot 0\times {{10}^{8}}V\,{{m}^{-1}}\] directed along the positive X-axis. The proton undergoes a displacement of \[0\centerdot 25m\] in the direction of E.

Mass of a proton =\[1\centerdot 66\times {{10}^{-27}}\,kg\] and charge of proton \[1\centerdot 6\times {{10}^{-19}}\,C\]

The Change in electric potential of the proton between the points A and B is

A) \[-1\times {{10}^{8}}V\]

B) \[1\times {{10}^{8}}V\]

C) \[6\centerdot 4\times {{10}^{-19}}V\]

D) \[-6\centerdot 4\times {{10}^{-19}}V\]