A) 1/2
B) 2
C) \[-2\]
D) -1/2
Correct Answer: C
Solution :
Here one equation of bisector is \[x-2y=0.\]We know that both bisectors are perpendicular, therefore second bisector will be \[2x+y=0\]because it passes through origin. Hence the combined equations of bisectors is given by \[(2x+y)(x-2y)=0\Rightarrow -2{{x}^{2}}+3xy+2{{y}^{2}}=0.\] Now comparing it by \[h{{x}^{2}}+3xy-h{{y}^{2}}=0\], we get h = ?2.You need to login to perform this action.
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