A) \[8{{x}^{2}}+11xy-8{{y}^{2}}=0\]
B) \[8{{x}^{2}}-11xy-8{{y}^{2}}=0\]
C) \[16{{x}^{2}}+11xy-16{{y}^{2}}=0\]
D) \[16{{x}^{2}}+11xy+16{{y}^{2}}=0\]
Correct Answer: A
Solution :
\[\frac{{{x}^{2}}-{{y}^{2}}}{11}=\frac{xy}{-8}\Rightarrow 8{{x}^{2}}+11xy-8{{y}^{2}}=0\].
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