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JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry / रसायन की कुछ मूलभूत अवधारणाएँ Question Bank Atomic Molecular and Equivalent masses

  • question_answer
    7.5 grams of a gas occupy 5.8 litres of volume at STP the gas is

    A)                 \[NO\]    

    B)                 \[{{N}_{2}}O\]

    C)                 \[CO\]     

    D)                 \[C{{O}_{2}}\]

    Correct Answer: A

    Solution :

               \[\because \] 5.8L of gas has mass \[=7.5gm\]                    \[\therefore \]22.4L   "      "       "     =\[\frac{7.5}{5.8}\times 22.4=28.96\]                    So molecular weight = 29                                 So, molecular formula of compound is NO


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