JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry Question Bank Atomic Molecular and Equivalent masses

  • question_answer
    The number of atoms in 4.25 g of \[N{{H}_{3}}\]is approximately [CBSE PMT 1999; MH CET 2003]

    A)                 \[1\times {{10}^{23}}\]    

    B)                 \[2\times {{10}^{23}}\]

    C)                 \[4\times {{10}^{23}}\]    

    D)                 \[6\times {{10}^{23}}\]

    Correct Answer: D

    Solution :

               \[\because \]  17gm \[N{{H}_{3}}\]contains \[6\times {{10}^{23}}\]molecules of \[N{{H}_{3}}\]                    \[\therefore \]  4.25gm \[N{{H}_{3}}\]contains = \[\frac{6\times {{10}^{23}}}{17}\times 4.25\]                                 \[\therefore \]  No. of atoms \[=\frac{6\times {{10}^{23}}\times 4.25}{17}\times 4\] \[=6\times {{10}^{23}}\].


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