A) \[\frac{n(a+b)}{2}\]
B) \[n(a+b)\]
C) \[\frac{(n+1)(a+b)}{2}\]
D) \[(n+1)(a+b)\]
Correct Answer: A
Solution :
The sum of \[n\] arithmetic mean between \[a\] and \[b\] \[=\frac{n}{2}(a+b)\]. Aliter: As we know\[{{A}_{1}}+{{A}_{2}}+......+{{A}_{n}}=nA\], where\[a=A{{R}^{p-1}},\ b=A{{R}^{q-1}}\].
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