A) \[\frac{n-1}{2}\]
B) \[\frac{n+1}{2}\]
C) \[\frac{n}{2}\]
D) \[n\]
Correct Answer: B
Solution :
A.M. \[=\frac{1+2+3+......+n}{n}=\frac{\frac{1}{2}n(n+1)}{n}=\frac{n+1}{2}\].
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