A) \[2\frac{1}{8}\]
B) \[3\frac{1}{8}\]
C) \[4\frac{1}{8}\]
D) \[5\frac{1}{8}\]
Correct Answer: C
Solution :
\[a+\frac{4}{a}=4\] \[{{a}^{2}}+4=4a\] \[{{a}^{2}}-4a+4=0\] \[{{(a-2)}^{2}}=0\] \[\therefore \]\[a=2\] Now, \[{{a}^{2}}+\frac{1}{{{a}^{3}}}\] \[{{2}^{2}}+\frac{1}{{{2}^{3}}}\] \[4+\frac{1}{8}\] \[4\frac{1}{8}\]You need to login to perform this action.
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