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6th Class Mathematics Algebra Question Bank Algebra

  • question_answer
    If \[x=y=z\] then find \[\frac{{{\left( x+y+z \right)}^{2}}}{{{x}^{2}}+{{y}^{2}}+{{z}^{2}}}\]

    A)  9                                

    B)  3

    C)  4                                

    D)  1

    Correct Answer: B

    Solution :

    \[x=y=z,\]then \[\frac{{{\left( x+y+z \right)}^{2}}}{{{x}^{2}}+{{y}^{2}}+{{z}^{2}}}=\frac{{{\left( x+x+x \right)}^{2}}}{{{x}^{2}}+{{x}^{2}}+{{x}^{2}}}=\frac{{{\left( 3x \right)}^{2}}}{3{{x}^{2}}}\] \[=\frac{9{{x}^{2}}}{3{{x}^{2}}}=3\]


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