A) \[-1\]
B) 2
C) 4
D) \[-3\]
Correct Answer: B
Solution :
\[\frac{1}{a+1}+\frac{2}{b+2}+\frac{1001}{c+1001}=1\] Subtracting both side by 3 \[\frac{1}{a+1}-1+\frac{2}{b+2}-1+\frac{1001}{c+1001}-1=4-3\] \[\frac{1-a-1}{a+1}+\frac{2-b-2}{b+2}+\frac{1001-c-1001}{c+1001}=-2\] \[\frac{-a}{a+1}+\frac{-b}{b+2}+\frac{-c}{c+1001}=-2\] \[-1\left( \frac{a}{a+1}+\frac{b}{b+2}+\frac{c}{c+1001} \right)=-2\] \[\frac{a}{a+1}+\frac{b}{b+2}+\frac{c}{c+1001}=2\]
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