A) 1
B) 2
C) 3
D) 4
Correct Answer: D
Solution :
\[\frac{x}{1-x}+\frac{y}{1-y}+\frac{z}{1-z}=1\] Adding both sides by 3 \[\frac{x}{1-x}+1+\frac{y}{1-y}+1+\frac{z}{1-z}+1=4\] \[\frac{x+1-x}{1-x}+\frac{y+1-y}{1-y}+\frac{z+1-z}{1-z}=4\] \[\frac{1}{1-x}+\frac{1}{1-y}+\frac{1}{1-z}=4\]You need to login to perform this action.
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