JEE Main & Advanced Mathematics Mathematical Logic and Boolean Algebra Logic Gates

Logic Gates

Category : JEE Main & Advanced

(i) AND : It is the boolean function defined by

 

\[f({{x}_{1}},{{x}_{2}})={{x}_{1}}\wedge {{x}_{2}}\]; \[{{x}_{1}},\,{{x}_{2}}\in \{0,\,1\}\].

 

It is shown in the figure given below.  

   

Input Output
\[{{x}_{1}}\] \[{{x}_{2}}\] \[{{x}_{1}}\wedge {{x}_{2}}\]
1 1 0 0 1 0 1 0 1 0 0 0

 

(ii) OR : It is the boolean function defined by

 

\[f({{x}_{1}},{{x}_{2}})={{x}_{1}}\vee {{x}_{2}}\]; \[{{x}_{1}},{{x}_{2}}\in \{0,\,1\}\].

 

It is shown in the figure given below  

 

            

Input Output
\[{{x}_{1}}\] \[{{x}_{2}}\] \[{{x}_{1}}\vee {{x}_{2}}\]
1 1 0 0 1 0 1 0 1 1 1 0

 

(iii) NOT : It is the boolean function defined by

 

\[f(x)={x}',\] \[x\in \{0.1\}\]

 

It is shown in the figure given below:   

    

Input Output
x 1 0 x¢ 0 1

 

Combinational circuit :  

     

In the above figure, output s in uniquely defined for each combination of inputs \[{{x}_{1}},{{x}_{2}}\] and \[{{x}_{3}}\]. Such a circuit is called a combinatorial circuit or combinational circuit.  

In the above figure, if \[{{x}_{1}}=1,{{x}_{2}}=0\], then the inputs to the AND gate are 1 and 0 and so the output of the AND gate is ‘0’ (Minimum of 1 and 0). This is the input of NOT gate which gives the output \[s=1\].

 

But the diagram states that \[{{x}_{2}}=s\] i.e. \[0=1\], a contradiction.

 

\[\therefore \]The output s is not uniquely defined. This type of circuit is not a combinatorial circuit.

 

Two combinatorial circuits : Circuit having inputs \[{{x}_{1}},{{x}_{2}},......{{x}_{n}}\] and a single output are said to be combinatorial circuit if, the circuits receive the same input, they produce the same output i.e., if the input/output tables are identical.


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