Notes - Mathematics Olympiads - Matrices and Determinant
Category : 11th Class
Matrices and Determinant
Key Points to Remember
Let us consider the linear equation
\[{{a}_{1}}x+{{b}_{1}}y={{c}_{1}}\] (i)
\[{{a}_{2}}x+{{b}_{2}}y={{c}_{2}}\] (ii)
We have one of the methods to solve these equation by cross multiplication method.
\[\frac{x}{{{b}_{1}}{{c}_{2}}-{{b}_{2}}{{c}_{1}}}=\frac{y}{{{c}_{1}}{{a}_{2}}-{{c}_{2}}{{a}_{1}}}=\frac{1}{{{a}_{1}}{{b}_{2}}-{{a}_{2}}{{b}_{1}}}\]
Now we modify this method & convert this method into standard form (matrix form)
Given linear equation can be solved by matrix method & it is written as,
\[AX=B\]
Generally matrix is represented by [ ] (square bracket) or ( ) etc.
Generally, it is represented as
\[A=[{{a}_{ij}}]\] \[i=1,\,2,\,3,....m\]
\[j=1,\,2,\,3,....n\]
Here subscript i denotes no. of row.
& subsrcipt j determines no. of column.
& \[{{a}_{ij}}\to \] represent the position of element a in the given matrix
e.g. \[A=[{{a}_{ij}}]\] & if \[i\le 3\] and \[i\le 2\]
Order of matrix \[A=3\times 2\] in which 3 determine number of row & 2 determine no. of column of given matrix.
Let \[A={{[{{a}_{ij}}]}_{m\times n}}\] & \[B={{[{{b}_{ij}}]}_{m\times n}}\] be two matrices, having same order.
Then \[A+B\] or \[B+A\] is a matrix whose elements be formed through corresponding addition of elements of two given matrices
\[A+B=B+A\]
Similarly for subtraction operation, we can subtracted two matrices.
But \[A-B\ne B-A\] i.e. \[A-B=-(B-A)\]
Note: For addition or substraction operation of two or more than two matrices. They (given matrix) should be the same order.
For multiplication of two matrices, no. of column of 1st matrix should be equal to no. of row of 2nd matrix. Otherwise multiplication of two matrix does not hold.
Then
\[A\times B-[{{c}_{ij}}]\]be a matrix whose order will be\[m\times p\].
e.g. \[A={{\left[ \xrightarrow[2\,\,\,\,\,\,\,\,\,2\,\,\,\,\,\,\,1]{2\,\,\,\,\,\,\,\,\,1\,\,\,\,\,\,\,\,3} \right]}_{2\times 3}}\]
\[\therefore \,\,\,A\times B\]
Hence \[A\times B\,\,\ne \,\,B\times A.\]
(a) Row Matrix: A matrix having order \[1\times n\] i.e.
Which has only one row, is said to be row matrix.
e.g. \[A={{\left[ 1\,\,\,2\,\,\,3\,\,\,4\,\,\,5 \right]}_{1\times 5}}\]
(b) Column Matrix: A matrix, having and
(m x 1) i.e. which has only one column is said to be column matrix.
(c) Square Matrix: A matrix having same no. of row & column is said to be square matrix.
(d) Diagonal Matrix: A square matrix is said to be diagonal matrix if its non-diagonal elements should be zero.
i.e. \[{{a}_{ij}}=0\] if \[i\ne j\]
= something if \[i=j\]
Let A is a matrix of order\[m\times n\]. Then the transpose of a matrix A is a matrix of order \[n\times m\] which is obtained by interchanging the rows & columns of matrix A. It is denoted by \[A'\] or \[{{A}^{Tau }}\]
(i) If A and B be the two matrix of the same order then \[{{(A\pm B)}^{Tau }}={{A}^{Tau }}\pm {{B}^{Tau }}\,\,\,m\times n\]
(ii) If A be the matrix and k be any scalar quantity then \[{{(\text{k}A)}^{Tau }}=\text{k}\text{.}{{\text{A}}^{Tau }}\]
(iii) If A & B be two matrix of order \[m\times n\] and \[n\times p\] respectively, there exists the multiplication between A & B. Then
\[{{(A\times B)}^{Tau }}={{B}^{Tau }}.{{A}^{Tau }}\]
(iv) The double transpose of any matrix gives its primal matrix i.e. \[{{({{A}^{Tau }})}^{Tau }}=A.\]
i.e. \[A=A'\]
It is represented by
The matrix, \[A={{[{{a}_{ij}}]}_{m\times n}}\] is said to symmetric matrix if \[{{a}_{ij}}={{a}_{j}}.\]
i.e. \[A=-A'\]
Symbolically, it is represented by
The matrix, \[A={{[{{a}_{ij}}]}_{m\times m}}\] is square matrix.
If \[{{a}_{ij}}=-{{a}_{ij}}\,\,\,\forall \,\,i\And \,j\]
e.g.
Note: Every square matrix is written as the sum of the symmetric & skew symmetric matrices.
i.e. If A is a square matrix
then \[A=\frac{1}{2}[(A+{{A}^{Tau }})+(A-{{A}^{Tau }})]\]
Where \[A+{{A}^{Tau }}=\] symmetric matrix
& \[A-{{A}^{Tau }}=\] skew symmetric matrix.
Properties of symmetric & skew symmetric matrix.
(i) lf A & B be two symmetric (skew symmetric) matrices A+B be symmetric matrix (skew symmetric matrix).
(ii) If A is symmetric (or skew symmetric) matrix and k is any scalar quantity, then (kA) is a symmetric (or skew symmetric) matrix.
(iii) If A and B are symmetric matrices of the same order, the product AB is symmetric iff AB = BA
(iv) The matrix B' AB is symmetric or skew symmetric according as A is symmetric or skew symmetric.
(v) If A and Bare symmetric metrices of the same order, then
(a) AB - BA is a skew symmetric matrix.
(b) AB + BA is a symmetric matrix.
(vi) All positive integral powers of a symmetric (skew symmetric) matrix will be symmetric (skew symmetric) matrix.
e.g.
Let \[A=[{{a}_{ij}}]\] be a square matrix of order m. Then B be a square matrix of order m whose element be the corresponding co-factor element of matrix A. Then the transpose of B is said to be the adjoint at the matrix A.
In \[{{R}_{1}}\] row,
co-factor of 1 i.e. \[{{a}_{11}}=3\]
co-factor of -1 i.e. \[{{a}_{12}}=-12\]
co-factor of 2 i.e. \[{{a}_{13}}=6\]
In \[{{R}_{2}}\] row,
co-factor of 2 i.e. \[{{a}_{21}}=-\,\,(-1)=2\]
co-factor of 3 i.e. \[{{a}_{22}}=5\]
co-factor of 5 i.e. \[{{a}_{23}}=-\,(-2)=2\]
In \[{{R}_{3}}\] row,
co-factor of - 2 i.e. \[{{a}_{31}}=-11\]
co-factor of 0 i.e. \[{{a}_{32}}=-(5-4)=-1\]
co-factor of 1 i.e. \[{{a}_{33}}=3+2=5\]
(i) If A is the square matrix of order m, then adjoint \[A'=(\text{adj}\,\,o\text{f}\,A)\]
(ii) If A & B be two the square matrices of the same order, then \[\text{adj}(AB)=(\text{adj}\,A).(\text{adj}\,B)\]
(iii) The adjoint if a diagonal matrix is a diagonal matrix.
(iv) \[\text{adj}\,\,(\text{adj}\,A)={{\left| \,A\, \right|}^{n-2}}.\] A where A is the non- singular matrix
\[AB=BA=\text{I}\]
Where I is the unit matrix.
i.e. It is represent by \[{{A}^{-1}}\]
So, \[{{A}^{-1}}=\frac{\text{adj}\,o\text{f}\,A}{\left| \,A\, \right|}\]
i.e. \[A.{{A}^{-1}}={{A}^{-1}}.A=\text{I}\]
(i) The inverse of the square a matrix exists iff A is non-singular.
(ii) Double inverse of the square matrix is primal matrix A itself.
i.e. \[{{\left( {{A}^{-1}} \right)}^{-1}}=A\]
(iii) If A & B be two invertiable matrices of the same order m x m then even AB is invertiable in the following order.
\[{{(AB)}^{-1}}={{B}^{-1}}{{A}^{-1}}\]
(iv) The inverse of the transpose of a matrix A is equal to the transpose of the inverse of matrix A.
i.e. \[{{(A')}^{-1}}=({{A}^{-1}})'\]
(v) If A is the symmetric matrix such that
\[\left| A \right|\ne 0\] then \[{{A}^{-1}}\] is the symmetric matrix.
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